C Program Tricked to Believe X equals X+2
The puzzle has been discussed previously, but only one solution was provided. But now I have added a few more solutions to this puzzle. The challenge is to get a true value for the following conditional statement.
x==x+2
You are free to use any feature of the C preprocessor or Compiler. If you can't get a solution then check the programs shown below.
Solution 1
#define x 2|0
#include<stdio.h>
int main()
{
if(x == x+2)
{
printf("\n Hello");
}
else
{
printf("\n Hi");
}
}
#include<stdio.h>
int main()
{
if(x == x+2)
{
printf("\n Hello");
}
else
{
printf("\n Hi");
}
}
Solution 2
#include<stdio.h>
int main()
{
float x=1.0/0;
if(x==x+2)
{
printf("\nHello");
}
else
{
printf("\nHi");
}
}
Solution 3
#include<stdio.h>
int main()
{
float x = 1e100;
if(x==x+2)
{
printf("\nHello");
}
else
{
printf("\nHi");
}
}
Solution 4
#include<stdio.h>
struct {}*x=0;
int main()
{
if(x==x+2)
{
printf("\nHello");
}
else
{
printf("\nHi");
}
}
Solution 5
#include<stdio.h>
int (*x)[0x20000000];
int main()
{
if(x==x+2)
{
printf("\nHello");
}
else
{
printf("\nHi");
}
}
Solution 6
#include<stdio.h>
int main()
{
/////////////////////////////////////
// we initialize tr = 1 //
int tr = 1;
int x = 111;
////////////////////////////////////
// Can You change the value of tr??/
tr = (x == x + 2);
/////////////////////////////////////
// The value of tr is not changed //
if(tr==1)
{
printf("\nHello");
}
else
{
printf("\nHi");
}
}
