Yet Another Difference Between C and C++: Initializing Constant Variables

  Constant variable initialization is yet another minute difference between C and C++. Consider the program given below.

#include<stdio.h>
int main()
{
  int x = 111;
  static int y = x;
  if(x == y)
     printf("Equal");
  else
     printf("Not Equal");
  return 0;
}

If you save the program as a C++ program, it compiles fine and shows the output as "Equal". But the same program when compiled as C will give you the following error "initializer element is not constant|". What is the reason? This is another minor difference between C and C++. In C a constant variable can only be initialized with a constant value and not by using another variable. But C++ do not have this restriction. You can initialize a constant variable with any other variable.

Click here to download the C++ program.

Yet Another Difference Between C and C++: Case Labels

 There are many major differences between C and C++. Such differences are matters for Text Books and Manuals. Here I am pointing out yet another minor difference between C and C++. This time the difference arises from the way case labels are treated in C and C++. 

 C++ will allow const int variables as case labels, whereas C will give you an error. Consider the program given below.

#include<stdio.h>

int main()
{
    int i=1;
    const int j=1;
    switch(i)
    {
        case j:
            printf("\nHello\n\n");
            break;
        case 2:
            printf("\nHi\n\n");
            break;
        default:
            printf("\nWelcome\n\n");
    }
    return 0;
}

The program will give the error 'case label does not reduce to an integer constant' when compiled as a C program. But when compiled as a C++ program the program executes without any errors and gives 'Hello' as output. 

C/C++ Puzzles: PART - 36

  The following program will give you syntax error.


#include<stdio.h>

int main()
{
    int a=10,b=5,c;
    c=a>b?a:;
    printf("\n%d\n\n",c);
    return 0;
}

Whereas the program given below will work without any syntax errors. Predict the output of the program.


#include<stdio.h>

int main()
{
    int a=10,b=5,c;
    c=a>b?:b;
    printf("\n%d\n\n",c);
    return 0;
}